20c^2-16c=48

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Solution for 20c^2-16c=48 equation:


Simplifying
20c2 + -16c = 48

Reorder the terms:
-16c + 20c2 = 48

Solving
-16c + 20c2 = 48

Solving for variable 'c'.

Reorder the terms:
-48 + -16c + 20c2 = 48 + -48

Combine like terms: 48 + -48 = 0
-48 + -16c + 20c2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-12 + -4c + 5c2) = 0

Factor a trinomial.
4((-6 + -5c)(2 + -1c)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-6 + -5c)' equal to zero and attempt to solve: Simplifying -6 + -5c = 0 Solving -6 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -5c = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -5c = 0 + 6 -5c = 0 + 6 Combine like terms: 0 + 6 = 6 -5c = 6 Divide each side by '-5'. c = -1.2 Simplifying c = -1.2

Subproblem 2

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {-1.2, 2}

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